document.write( "Question 756138: You are designing a rectangular birthday card for a friend. You want the card's length to be 1 in. more than twice the card's width. The area of the card is 88 in.^2. What are the dimensions of the card? Round to the nearest tenth if necessary.
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Algebra.Com's Answer #460018 by stanbon(75887)\"\" \"About 
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You are designing a rectangular birthday card for a friend. You want the card's length to be 1 in. more than twice the card's width. The area of the card is 88 in.^2. What are the dimensions of the card? Round to the nearest tenth if necessary.
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\n" ); document.write( "Width = x
\n" ); document.write( "length 2x+1
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\n" ); document.write( "Equation:
\n" ); document.write( "x(2x+1) = 88
\n" ); document.write( "2x^2 + x - 88 = 0
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\n" ); document.write( "x = [-1 +- sqrt(1-4*2*-88)}/4
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\n" ); document.write( "x = [-1 +- sqrt(1+704)]/4
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\n" ); document.write( "x = [-1 +- 26.55]/4
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\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 25.55/5
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\n" ); document.write( "x = 5.11 inches
\n" ); document.write( "x+1 = 6.11 inches
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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