document.write( "Question 756054: When an object is released and falls freely, its height , h metres, above the ground after t seconds is represented by the relation h = -0.5t2g + d , where g is the acceleration due to gravity and d is the initial height of the object before it is released. Since the strength of gravity varies from planet to planet, the value of g is specific to each planet. \r
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document.write( "Suppose a rock is dropped from a height of 100 m on Mars and also on Venus.
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document.write( "On Mars, g= 3.7m/s2 and on Venus, g= 8.9 m/s2. How long does it take the rock to fall to a height of 25 m on each planet ? \n" );
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Algebra.Com's Answer #459983 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! When an object is released and falls freely, its height , h metres, above the ground after t seconds is represented by the relation h = -0.5t2g + d , where g is the acceleration due to gravity and d is the initial height of the object before it is released. Since the strength of gravity varies from planet to planet, the value of g is specific to each planet. \r \n" ); document.write( "\n" ); document.write( "Suppose a rock is dropped from a height of 100 m on Mars and also on Venus. \n" ); document.write( "On Mars, g= 3.7m/s2 and on Venus, g= 8.9 m/s2. How long does it take the rock to fall to a height of 25 m on each planet ? \n" ); document.write( "============== \n" ); document.write( "On Mars, g= 3.7m/s2 \n" ); document.write( "h(t) = -1.85t^2 + 100 = 25 \n" ); document.write( "t^2 = 75/1.85 \n" ); document.write( "t =~ 6.367 seconds \n" ); document.write( "------- \n" ); document.write( "Do Venus the same way. \n" ); document.write( " \n" ); document.write( " |