document.write( "Question 756089: Trying to find the line prependicular to 3/4x-1. The reciprocal for the slope is -4/3x. Placed the given point (4,0) and the slope into the point slope form of a linear equation y-y1=m(x-x1) and get -4/3x+16/3. I'm stuck after that. Do I make the improper fraction a mixed number of leave it improper? Help please \n" ); document.write( "
Algebra.Com's Answer #459982 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+y+=+%283%2F4%29%2Ax+-+1+\"
\n" ); document.write( "Slope of perpendicular is \"+-4%2F3+\"
\n" ); document.write( "Goes through ( 4,0 )
\n" ); document.write( "Using point-slope formula:
\n" ); document.write( "\"+%28+y+-+0+%29+%2F+%28+x+-+4+%29+=+-4%2F3+\"
\n" ); document.write( "Multiply both sides by \"+3%2A%28+x-4+%29+\"
\n" ); document.write( "\"+3y+=+-4%2A%28+x-4+%29+\"
\n" ); document.write( "\"+3y+=+-4x+%2B+16+\"
\n" ); document.write( "\"+y+=+%28-4%2F3%29%2Ax+%2B+16%2F3+\"
\n" ); document.write( "That's it- it's as complete as you can get it.
\n" ); document.write( "Good job
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