document.write( "Question 65486: Subtract and express in simplest form\r
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document.write( " 3 - 1
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document.write( "x^2+4x+3 x^2-9\r
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document.write( "3-1 = 2
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document.write( "x^2 and x^2 cancel each other out leaving me with 4x+3 and -9
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document.write( "4x + 3 = 7x
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document.write( "Giving me the problem of:
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document.write( "2
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document.write( "7x
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document.write( "Is this the right way of doing it and the right answer?
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Algebra.Com's Answer #45998 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Subtract and express in simplest form\r \n" ); document.write( "\n" ); document.write( " 3 - 1 \n" ); document.write( "--------- --------- \n" ); document.write( "x^2+4x+3 x^2-9\r \n" ); document.write( "\n" ); document.write( "----------------- \n" ); document.write( "Factor the denominators as follows: \n" ); document.write( "[3/(x+3)(x+1)]-[1/(x-3)(x+3)] \n" ); document.write( "You can't do the subtraction till you get the same \n" ); document.write( "denominator on the two fractions. \n" ); document.write( "-------- \n" ); document.write( "The least common denominator is (x+1)(x+3)(x-3) \n" ); document.write( "--------------- \n" ); document.write( "Re-write each fraction with the lcd as its denominator, as follows: \n" ); document.write( "=[3(x-3)/lcd]-[(x+1)/lcd] \n" ); document.write( "----------- \n" ); document.write( "Now you can perform the subraction as follows: \n" ); document.write( "=[3x-9-x-1]/lcd \n" ); document.write( "=[2x-10]/[(x+1)(x+3)(x-3)] \n" ); document.write( "------------ \n" ); document.write( "That's as far as you can go with this messy problem. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |