document.write( "Question 756050: Please help me solve the linear inequality.
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document.write( "x/3 + 5x/6 < 2/3 \n" );
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Algebra.Com's Answer #459971 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! x/3 + 5x/6 < 2/3\r \n" ); document.write( "\n" ); document.write( "multiply both sides of the < by 6 (least common multiple of the denominators)\r \n" ); document.write( "\n" ); document.write( "2x + 5x < 4 (the < stays as a < sign because 6 is positive)\r \n" ); document.write( "\n" ); document.write( "7x < 4 and\r \n" ); document.write( "\n" ); document.write( "x < 4/7 or .57\r \n" ); document.write( "\n" ); document.write( "draw your number line and shade it to the left of the point .57, in other words, all x less than .57\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |