document.write( "Question 756020:  The domain of g(x)= (square roof of x-2/x^2 - 2x)is. 
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document.write( "(a) All x except 0 and 2
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document.write( "(b) all x except 0
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document.write( "(c) x <= 2 (less than or equal to)
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document.write( "(d) x>2
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document.write( "(e) x >= 2 (greater than or equal to) \r
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document.write( "I picked A. I took x^2 - 2x = 0 and got x(x-2)=0. took x-2=0 and solved for x and got x=2 but now I'm not sure... Can you please tell me if im right, and if not show me how to do it?  \n" );
document.write( "
Algebra.Com's Answer #459959 by solver91311(24713)    You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your denominator does indeed exclude 0 and 2, but the argument of a square root function must be greater than or equal to zero. Hence, the x cannot be less than 2 or the numerator is not defined. So relying only on the numerator, you have x >= 2, but since the denominator excludes x = 2, you are left with x > 2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "And just an \"oh by the way\", it is square rooT, not square rooF.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "  |