document.write( "Question 65465This question is from textbook Essential Algebra
\n" ); document.write( ": Joannie wants to enclose a rectangular area with 408 meters of fencing. If the width is 24 metes less than the length, what will the length and width of the enclosed area be? \n" ); document.write( "
Algebra.Com's Answer #45990 by uma(370)\"\" \"About 
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Let the length of the field be x m
\n" ); document.write( "Then the width = (x - 20)m\r
\n" ); document.write( "\n" ); document.write( "The perimeter = 2(l + w)
\n" ); document.write( " = 2(x + x - 20)
\n" ); document.write( " = 2(2x - 20)\r
\n" ); document.write( "\n" ); document.write( "Given the perimeter = 408.
\n" ); document.write( "THus the equation is 2(2x - 20) = 408
\n" ); document.write( " ==> 2x - 20 = 204 [dividing by 2 throughout]
\n" ); document.write( " ==> x - 10 = 102 [dividing by 2 again]
\n" ); document.write( "==> x = 102 + 10 [adding 10 to both the sides]
\n" ); document.write( "==> x = 112\r
\n" ); document.write( "\n" ); document.write( "Thus the length of the field = 112 m\r
\n" ); document.write( "\n" ); document.write( "The width = x - 20
\n" ); document.write( " = 112 - 20
\n" ); document.write( " = 92 m\r
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\n" ); document.write( "\n" ); document.write( "Good Luck !!!\r
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