document.write( "Question 754645: Find the vertex and the focus of the parabola x^2=-16y. \n" ); document.write( "
Algebra.Com's Answer #459893 by lwsshak3(11628)\"\" \"About 
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Find the vertex and the focus of the parabola x^2=-16y.
\n" ); document.write( "This is an equation of a parabola that opens downward with vertex at (0,0)
\n" ); document.write( "Its basic form: x^2=-4py
\n" ); document.write( "For given equation:
\n" ); document.write( "Axis of symmetry: x=0
\n" ); document.write( "4p=16
\n" ); document.write( "p=4
\n" ); document.write( "focus: (0,-4) (p-distance below vertex on the axis of symmetry)
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