document.write( "Question 754645: Find the vertex and the focus of the parabola x^2=-16y. \n" ); document.write( "
Algebra.Com's Answer #459893 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the vertex and the focus of the parabola x^2=-16y. \n" ); document.write( "This is an equation of a parabola that opens downward with vertex at (0,0) \n" ); document.write( "Its basic form: x^2=-4py \n" ); document.write( "For given equation: \n" ); document.write( "Axis of symmetry: x=0 \n" ); document.write( "4p=16 \n" ); document.write( "p=4 \n" ); document.write( "focus: (0,-4) (p-distance below vertex on the axis of symmetry) \n" ); document.write( " |