document.write( "Question 755374: ln(x-3)<0 if and only if
\n" ); document.write( "(a) x<4
\n" ); document.write( "(b) x>3
\n" ); document.write( "(c) x>4
\n" ); document.write( "(d) 1\n" ); document.write( "(e) 3\n" ); document.write( "

Algebra.Com's Answer #459875 by KMST(5328) $\"\"$ $\"About$

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$\"f%284%29=ln%284-3%29=ln%281%29=0\"$
\n" ); document.write( " $\"f%28x%29=ln%28x-3%29\"$ increases as $\"x\"$ increases thoughout the (3,infinity) domain of the function.
\n" ); document.write( " $\"x%3C4\"$ <--> $\"f%28x%29%3C0\"$
\n" ); document.write( " $\"x=4\"$ <--> $\"f%28x%29=0\"$
\n" ); document.write( " $\"x%3E4\"$ <--> $\"f%28x%29%3E0\"$
\n" ); document.write( "So $\"f%28x%29=ln%28x-3%29%3C0\"$ means $\"highlight%28x%3C4%29\"$ \n" ); document.write( "

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