document.write( "Question 755849: A coffee merchant combines coffee costing $6 per pound with coffee cost $3.50 per pound. How many pounds of each should be used to make 50lb of a blend costing $4.20 per pound? \n" ); document.write( "
Algebra.Com's Answer #459859 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = pounds of $6/pound coffee needed
\n" ); document.write( "Let \"+b+\" = pounds of $3.50/pound coffee needed
\n" ); document.write( "\"+6a+\" = cost of $6/pound coffee in blend
\n" ); document.write( "\"+3.5b+\" = cost of $3.50/pound coffee in blend
\n" ); document.write( "----------------
\n" ); document.write( "(1) \"+a+%2B+b+=+50+\"
\n" ); document.write( "(2) \"+%28+6a+%2B+3.5b+%29+%2F+50+=+4.2+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "(2) \"++6a+%2B+3.5b+=+4.2%2A50+\"
\n" ); document.write( "(2) \"++60a+%2B+35b+=+2100+\"
\n" ); document.write( "Multiply both sides of (1) by
\n" ); document.write( "\"+35+\" and subtract (1) from (2)
\n" ); document.write( "(2) \"++60a+%2B+35b+=+2100+\"
\n" ); document.write( "(1) \"+-35a+-+35b+=+-1750+\"
\n" ); document.write( "\"+25a+=+350+\"
\n" ); document.write( "\"+a+=+14+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+a+%2B+b+=+50+\"
\n" ); document.write( "(1) \"+14+%2B+b+=+50+\"
\n" ); document.write( "(1) \"+b+=+36+\"
\n" ); document.write( "14 pounds of $6/pound coffee are needed
\n" ); document.write( "36 pounds of $3.50/pound coffee are needed
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+6a+%2B+3.5b+%29+%2F+50+=+4.2+\"
\n" ); document.write( "(2) \"+%28+6%2A14+%2B+3.5%2A36+%29+%2F+50+=+4.2+\"
\n" ); document.write( "(2) \"+%28+84+%2B+126+%29+%2F+50+=+4.2+\"
\n" ); document.write( "(2) \"+210+=+4.2%2A50+\"
\n" ); document.write( "(2) \"+210+=+210+\"
\n" ); document.write( "OK
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