document.write( "Question 755750: how do i solve (1/36)^x-1 =1296^2x \n" ); document.write( "
Algebra.Com's Answer #459818 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"%281%2F36%29%5E%28x-1%29+=1296%5E%282x%29\".......write \"%281%2F36%29%5Ex-1\" as \"36%5E%281-x%29\" and \"1296\" as \"36%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"36%5E%281-x%29+=%2836%5E2%29%5E%282x%29\" .........since \"%2836%5E2%29%5E%282x%29=%2836%29%5E%284x%29\" we have\r
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\n" ); document.write( "\n" ); document.write( "\"36%5E%281-x%29+=36%5E%284x%29\"..since bases same, exponents are same too; so, we have\r
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\n" ); document.write( "\n" ); document.write( "\"1-x+=4x\"....solve for \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"1=4x%2Bx\"\r
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\n" ); document.write( "\n" ); document.write( "\"1=5x\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F5=x\"\r
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