document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65439>Question 65439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the pressure,p, on a diver in the water varies directly as the depth,d. if the pressure is 6 lb/sq.in. when the depth is 12 feet, what is the pressure when the depth is 16 ft? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45981 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the pressure,p, on a diver in the water varies directly as the depth,d. if the pressure is 6 lb/sq.in. when the depth is 12 feet, what is the pressure when the depth is 16 ft?<BR>\n" );
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document.write( "p=kd<BR>\n" );
document.write( "Need find \"k\".<BR>\n" );
document.write( "6=k12<BR>\n" );
document.write( "k=1/2<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "p=(1/2)d<BR>\n" );
document.write( "If the depth is 16 ft,<BR>\n" );
document.write( "p=(1/2)(16)=8 lb/sq.in<BR>\n" );
document.write( "cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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