document.write( "Question 65458: solve: \r
\n" ); document.write( "\n" ); document.write( "x^2-y^2=4
\n" ); document.write( "x+y=1
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Algebra.Com's Answer #45977 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1st: x^2-y^2=4
\n" ); document.write( "2nd: x+y=1
\n" ); document.write( "Divide 1st by 2nd to get:
\n" ); document.write( "3rd: x-y=4
\n" ); document.write( "-------------
\n" ); document.write( "Add 2nd and 3rd to get:
\n" ); document.write( "4th: 2x=5
\n" ); document.write( "x=5/2
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\n" ); document.write( "Substitute into 2nd to get:
\n" ); document.write( "(5/2)+y=1
\n" ); document.write( "y=-3/2
\n" ); document.write( "-------------
\n" ); document.write( "Solution: x=5/2 ; y=-3/2
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\n" ); document.write( "Checking the solution:
\n" ); document.write( "1st: x^2-y^2=4
\n" ); document.write( "(5/2)^2-(-3/2)^2=4
\n" ); document.write( "25/4 - 9/4 = 4
\n" ); document.write( "16/4 = 4
\n" ); document.write( "4=4
\n" ); document.write( "-----------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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