document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=755638>Question 755638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is 5 feet less than its length. Find its width if the perimeter is 54 feet.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #459760 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=459760\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is 5 feet less than its length. Find its width if the perimeter is 54 feet.<BR>\n" );
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document.write( "length = L<BR>\n" );
document.write( "width = L-5<BR>\n" );
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document.write( "Perimeter = 2(L+W)<BR>\n" );
document.write( "54 = 2(L + L-5)<BR>\n" );
document.write( "27 = 2L - 5<BR>\n" );
document.write( "2L = 32<BR>\n" );
document.write( "L = length = 16 ft.<BR>\n" );
document.write( "W = width = L-5 = 11 ft<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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