document.write( "Question 755554: john has twin sisters, grace & gina. in four years john will be twice as old as the twins are now. last year grace was 2/3rds of johns age. how old are each of the siblings \n" ); document.write( "
Algebra.Com's Answer #459758 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! john has twin sisters, grace & gina. \n" ); document.write( "in four years john will be twice as old as the twins are now. \n" ); document.write( "last year grace was 2/3rds of johns age. how old are each of the siblings \n" ); document.write( ": \n" ); document.write( "let j = John's age \n" ); document.write( "let t = twin's age \n" ); document.write( ": \n" ); document.write( "\"in four years john will be twice as old as the twins are now.\" \n" ); document.write( "j + 4 = 2t \n" ); document.write( "j + 4 = 2t \n" ); document.write( "j = 2t \n" ); document.write( "j = 2t - 4 \n" ); document.write( ": \n" ); document.write( "\"last year grace was 2/3rds of johns age.\" \n" ); document.write( "t - 1 = \n" ); document.write( "multiply both sides by 3 \n" ); document.write( "3(t-1) = 2(j-1) \n" ); document.write( "3t - 3 = 2j - 2 \n" ); document.write( "3t = 2j - 2 + 3 \n" ); document.write( "3t = 2j + 1 \n" ); document.write( "Replace j with (2t-4) \n" ); document.write( "3t = 2(2t-4) + 1 \n" ); document.write( "3t = 4t - 8 + 1 \n" ); document.write( "3t = 4t - 7 \n" ); document.write( "7 = 4t-3t \n" ); document.write( "t = 7 yrs old is the twin's age \n" ); document.write( "; \n" ); document.write( "how old are each of the siblings? they're twins they are the same age! \n" ); document.write( " \n" ); document.write( " |