document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=755542>Question 755542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation of the line containing the given point and perpendicular to the given line.  Express your answer in the form y=mx+b.  (8,9); 6x+y=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #459752 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=459752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6x+y=2<BR>\n" );
document.write( "Put into y = mx +c form<BR>\n" );
document.write( "y = -6x + 2<BR>\n" );
document.write( "Gradient (m) =-6<BR>\n" );
document.write( "If a line is perpendicular to another<BR>\n" );
document.write( "their gradients multiply together to<BR>\n" );
document.write( "make -1  (m1 x m2 = -1)<BR>\n" );
document.write( "Therefore m2 = 1/6<BR>\n" );
document.write( "Using formula y - b = m(x - a)<BR>\n" );
document.write( "and coordinates (8,9)<BR>\n" );
document.write( "y - 9 = 1/6(x - 8)<BR>\n" );
document.write( "y - 9 =1/6x - 8/6<BR>\n" );
document.write( "    y = 1/6x - 8/6 + 9<BR>\n" );
document.write( "    y = 1/6x + 46/6<BR>\n" );
document.write( "  OR 6y = x + 46<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );