document.write( "Question 755579: HOW DO YOU Find the x- and y-intercepts for the line given by the equation 3x + 4y = 12 and use them to graph the line. Using the plotting applet in Bogomolny (2012a)? \n" ); document.write( "
Algebra.Com's Answer #459721 by reviewermath(1029)\"\" \"About 
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"3+x+%2B+4+y+=+12\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-3%2F4\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 12/3 = 4.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 12/4 = 3.
  • Slope is -3/4 = -0.75.
  • Equation in slope-intercept form: y=-0.75*x+3.
\"graph%28+500%2C+500%2C+4-8%2C+4%2B8%2C+3-8%2C+3%2B8%2C+-0.75%2Ax%2B3+%29+\"\n" ); document.write( "
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