document.write( "Question 755505: please me college algebra
\n" ); document.write( "find the domain for: f(x)= (sqrt(x-5))/3\r
\n" ); document.write( "\n" ); document.write( "range for: y=-2x^2 + 8
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Algebra.Com's Answer #459707 by josgarithmetic(39620)\"\" \"About 
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Domain for \"f%28x%29=+%28sqrt%28x-5%29%29%2F3\" means, the set of values that x can be. If you are only dealing in real numbers, then the restriction is that x-5>=0, meaning x>=5. The domain is then the set of all real numbers greater than or equal to 5. As done in interval notation, the domain is [+5, infin). \n" ); document.write( "
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