document.write( "Question 755483: The owner wants to create 140 pounds of mixture of peanuts and cashews that he plans on selling for $11.35 per pound. The peanuts sell for $9 per pound and the cashews sell for $12 per pound. How many pounds of each must he mix together to break even. \n" ); document.write( "
Algebra.Com's Answer #459682 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
This is like a mixture concentration problem in which the concentration is dollars per pound.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "p for peanuts
\n" ); document.write( "c for cashews\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%289%2Ap%2B11.35%2Ac%29%2F140=12\" and \"p%2Bc=140\" which should be enough to start.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To continue, \"9p%2B11.35c=140%2A12\" and \"c=140-p\" so substitute,
\n" ); document.write( "\"9p%2B11.35%28140-p%29=140%2A12\"
\n" ); document.write( "\"9p%2B%2811.35%29%2A140-%2811.35%29%2Ap=140%2A12\"
\n" ); document.write( "and you can continue through this to solve for p, and then go back to solve for c.
\n" ); document.write( "
\n" );