document.write( "Question 755453: In a play, 30% of the audience are female. If there are 500 more males than females, what is the total audience? \n" ); document.write( "
Algebra.Com's Answer #459679 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! In a play, 30% of the audience are female. If there are 500 more males than females, what is the total audience? \n" ); document.write( "------------------------ \n" ); document.write( "Equations: \n" ); document.write( "m = f + 500 \n" ); document.write( "f = 0.3(m+f) \n" ); document.write( "-------- \n" ); document.write( "Substitue for \"m\" and solve for \"f\" \n" ); document.write( "f = 0.3(f+500) + 0.3f \n" ); document.write( "---- \n" ); document.write( "10f = 3f + 1500 + 3f \n" ); document.write( "4f = 1500 \n" ); document.write( "f = 375 (# of females) \n" ); document.write( "m = f + 500 = 875 (# of males) \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |