document.write( "Question 755453: In a play, 30% of the audience are female. If there are 500 more males than females, what is the total audience? \n" ); document.write( "
Algebra.Com's Answer #459679 by stanbon(75887)\"\" \"About 
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In a play, 30% of the audience are female. If there are 500 more males than females, what is the total audience?
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\n" ); document.write( "Equations:
\n" ); document.write( "m = f + 500
\n" ); document.write( "f = 0.3(m+f)
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\n" ); document.write( "Substitue for \"m\" and solve for \"f\"
\n" ); document.write( "f = 0.3(f+500) + 0.3f
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\n" ); document.write( "10f = 3f + 1500 + 3f
\n" ); document.write( "4f = 1500
\n" ); document.write( "f = 375 (# of females)
\n" ); document.write( "m = f + 500 = 875 (# of males)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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