document.write( "Question 755335: I have a chemical that is a 40% concentrate, (40% active ingredient 60% water). I need to make one gallon of product that is 99.50% water and .50% of the active chemical. \n" ); document.write( "
Algebra.Com's Answer #459621 by ankor@dixie-net.com(22740)\"\" \"About 
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I have a chemical that is a 40% concentrate,
\n" ); document.write( " (40% active ingredient 60% water).
\n" ); document.write( " I need to make one gallon of product that is 99.50% water and .50% of
\n" ); document.write( " the active chemical
\n" ); document.write( ":
\n" ); document.write( "Let w = amt of pure water required
\n" ); document.write( "then
\n" ); document.write( "(1-w) = amt of original mixture required
\n" ); document.write( ":
\n" ); document.write( "Write a mixture equation based on the amt of water, (decimal equiv)
\n" ); document.write( ".60(1-w) + w = .995(1)
\n" ); document.write( ".6 - .6w + w = .995
\n" ); document.write( "-.6w + 1w = .995 - .6
\n" ); document.write( ".4w = .395
\n" ); document.write( "w = .395/.4
\n" ); document.write( "w = .9875 gal of water
\n" ); document.write( "and
\n" ); document.write( "1 - .9875 = .0125 gal of the original mixture
\n" ); document.write( ":
\n" ); document.write( "It may be easier to have these two amts in ounces, (32 oz = 1 qt)
\n" ); document.write( ".9875(32) = 31.6 oz of water
\n" ); document.write( ".0125(32) = .4 oz of original mixture \n" ); document.write( "
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