document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=755350>Question 755350</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We have a right isosceles triangle with the heighth of 3 and the base is 12 what is the perimeter?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #459614 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=459614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A right angled triangle with height = 3 units<BR>\n" );
document.write( "and a base = 12 units.<BR>\n" );
document.write( "We find the hypotenuse, which is the third side<BR>\n" );
document.write( "facing the 90 degree right angle.<BR>\n" );
document.write( "Hypotenuse^2 = 3^2 + 12^2<BR>\n" );
document.write( " Hypotenuse^2 = 153<BR>\n" );
document.write( "    Hypotenuse = square root of 153<BR>\n" );
document.write( "    Hypotenuse = 12.4 units<BR>\n" );
document.write( "The perimeter = 2( 12.4) + 12 units<BR>\n" );
document.write( "            = 36.8 units.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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