document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=755290>Question 755290</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I want to see the steps on solving this problem; 6((2y/3))-3y+2=0. <BR>\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #459582 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=459582\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6((2y/3))-3y+2=0. <BR>\n" );
document.write( "In the brackets the external 6<BR>\n" );
document.write( "is cancelled down to 2 by the 3<BR>\n" );
document.write( "below the 2y. <BR>\n" );
document.write( " 3(2y) - 3y + 2 = 0<BR>\n" );
document.write( "   6y - 3y + 2 = 0<BR>\n" );
document.write( "Collect like terms<BR>\n" );
document.write( "      3y   + 2 = 0<BR>\n" );
document.write( "            3y = -2<BR>\n" );
document.write( "             y = -2/3<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );