document.write( "Question 755197: [(1+b)/b](x) + [(1+a)/a](y) = b-a
\n" ); document.write( "x/a - 4y/b = 5\r
\n" ); document.write( "\n" ); document.write( "Need help please. I got this problem in a linear equation worksheet. But as the equation has a degree of more than one, i'm posting this here. Please help as soon as possible.
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Algebra.Com's Answer #459542 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
Those equations have x and y to degree 1. Each equation can be simplified but the degrees on x and y will still be 1. \r
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\n" ); document.write( "\n" ); document.write( "[(1+b)/b](x) + [(1+a)/a](y) = b-a
\n" ); document.write( "As rendered should be as
\n" ); document.write( "\"%28%281%2Bb%29%2Fb%29%28x%29+%2B+%28%281%2Ba%29%2Fa%29%28y%29+=+b-a\"
\n" ); document.write( "Multiply both sides by \"a%2Ab\" to clear the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2Fa+-+4y%2Fb+=+5\"
\n" ); document.write( "See the l.c.d. is also \"a%2Ab\", so multiply both sides by \"a%2Ab\" to clear the fractions.\r
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\n" ); document.write( "\n" ); document.write( "I'll jump ahead some, since you may already know how to clear the fractions and simplify each of these simultaneous equations. You will find you have this system linear in x and y, exponent on x and y being 1:\r
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\n" ); document.write( "\"a%281%2Bb%29x%2Bb%281%2Ba%29y=ab%5E2-ba%5E2\"
\n" ); document.write( "AND
\n" ); document.write( "\"bx-4ay=5ab\"
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\n" ); document.write( "\n" ); document.write( "I would recommend solving the second equation for either x or y and subsitute into the first equation and solve for the single variable there; and then solve for the other variable. I'll give one of those pathways here:\r
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\n" ); document.write( "\n" ); document.write( "\"bx-4ay%2B4ay=5ab%2B4ay\"
\n" ); document.write( "\"bx=5ab%2B4ay\"
\n" ); document.write( "\"x=%285ab%2B4ay%29%2Fb\"
\n" ); document.write( "and substitute this for x in the other equation.\r
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\n" ); document.write( "\n" ); document.write( "\"a%281%2Bb%29x%2Bb%281%2Ba%29y=ab%5E2-ba%5E2\"
\n" ); document.write( "\"a%281%2Bb%29%281%2Fb%29%285ab%2B4ay%29%2Bb%281%2Ba%29y=ab%5E2-ba%5E2\"
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\n" ); document.write( "Many very detailed simplification steps too difficult to show in typed text form, so done on paper, yielding this not necessarily finished solution for only y:
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\n" ); document.write( "\"y=b%28ab%5E2-ba%5E2-5a%5E2%281%2Ba%29%29%2F%284a%5E2%281%2Bb%29%2Bb%5E2%281%2Ba%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Seems to have no special useful factorizations there so the best simplification is
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\n" ); document.write( "\n" ); document.write( "Best way to find x is to go back to the second equation and solve that for y and substitute into the first equation and go through the long steps to solve for a formula for x.
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