document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=755218>Question 755218</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Q1Q3   IN A SQUARE ABCD ,AB=(2x+3)CM BC =(3x-5)CM .FIND THE PERIMETER OF ABCD.''.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #459535 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10557)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=459535\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Q1Q3   IN A SQUARE ABCD ,AB=(2x+3)CM BC =(3x-5)CM .FIND THE PERIMETER OF ABCD.''\r<BR>\n" );
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document.write( "Being a square with one side equaling 2x + 3, and the other, 3x - 5, then:\r<BR>\n" );
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document.write( "2x + 3 = 3x - 5\r<BR>\n" );
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document.write( "2x - 3x = - 5 - 3\r<BR>\n" );
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document.write( "- x = - 8\r<BR>\n" );
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document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-+8%29%2F-+1 ALIGN=MIDDLE  ALT=\"%28-+8%29%2F-+1\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or 8 \r<BR>\n" );
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document.write( "One side of square = 2(8) + 3, or 16 + 3, or 19 cm\r<BR>\n" );
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document.write( "Perimeter = 19(4), or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2876%29 ALIGN=MIDDLE  ALT=\"highlight_green%2876%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > cm </SPAN>\n" );
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