document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=755114>Question 755114</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Number 58 on the worksheet found at this link! : \r<BR>\n" );
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document.write( "http://www.phuhs.org/teachers/weaversu/FR1.htm \r<BR>\n" );
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document.write( "I need to know how to solve it and the answer. Thank you so much!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #459519 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=459519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two dotted lines (OA and OB) and the arc AB form the border of a sector (a piece of pie) with AB as a curved border.<BR>\n" );
document.write( "The area of that sector is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F4 ALIGN=MIDDLE  ALT=\"1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > of the area of the circle, because the measure of arc AB is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90%5Eo ALIGN=MIDDLE  ALT=\"90%5Eo\"   DISABLED_style= \"max-width:90%; height:auto;\" > and that is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F4 ALIGN=MIDDLE  ALT=\"1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > of the <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=360%5Eo ALIGN=MIDDLE  ALT=\"360%5Eo\"   DISABLED_style= \"max-width:90%; height:auto;\" > measure of the whole circumference.<BR>\n" );
document.write( "The area of a circle is calculated as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2Aradius%5E2 ALIGN=MIDDLE  ALT=\"pi%2Aradius%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "In this case, the area of the circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A%28sqrt%282%29%29%5E2=pi%2A2=2pi ALIGN=MIDDLE  ALT=\"pi%2A%28sqrt%282%29%29%5E2=pi%2A2=2pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > square units.<BR>\n" );
document.write( "Then, the area of the sector with AB as a curved border is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F4%29%282pi%29=pi%2F2 ALIGN=MIDDLE  ALT=\"%281%2F4%29%282pi%29=pi%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > square units.<BR>\n" );
document.write( "Triangle OAB is an isosceles right triangle.<BR>\n" );
document.write( "The angle at O is a right angle.<BR>\n" );
document.write( "The length of each leg is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=OA=OB=sqrt%282%29 ALIGN=MIDDLE  ALT=\"OA=OB=sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > units.<BR>\n" );
document.write( "Taking one leg as the base of the triangle, the other leg would be the height, and the area of triangle OAB is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29%2Abase%2Aheight=%281%2F2%29%2A%28sqrt%282%29%29%2A%28sqrt%282%29%29=%281%2F2%29%2A2=1 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > square units.<BR>\n" );
document.write( "The area of the shaded part is the area of sector OAB minus the area of triangle OAB.<BR>\n" );
document.write( "It is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28pi%2F2-1%29 ALIGN=MIDDLE  ALT=\"highlight%28pi%2F2-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > square units. </SPAN>\n" );
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