document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65374>Question 65374</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0073016020/algebrahomeworkh>Beginning Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Write each expression in simplest form:\r<BR>\n" );
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document.write( "I believe I follow the same factoring for fractions which shows:<BR>\n" );
document.write( "4*1*x and 4*2*4 <BR>\n" );
document.write( "5*1*x and 5*7\r<BR>\n" );
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document.write( "This would leave me:<BR>\n" );
document.write( "4 and 4*2*4<BR>\n" );
document.write( "5 and 5*7<BR>\n" );
document.write( "giving me the answer of:<BR>\n" );
document.write( "4(4*2*4)<BR>\n" );
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document.write( "5(5*7)\r<BR>\n" );
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document.write( "Is this correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45951 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note : 4*2*4 is not equal to 28.<BR>\n" );
document.write( "The  factors are the terms which multiply together to give the required expression.\r<BR>\n" );
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document.write( "To get the factors of 4x - 28 look for a common factor in each term. You should notice that 4 will go into both 4x and 28. You can therefore write down 4 as one of the factors. You now check what 4 will need to be multiplied by to give 4x + 28. To get the 4x you need to multiply by x and to get -28 you need to multiply by -7. The two factors are therefore 4 and (x-7)\r<BR>\n" );
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document.write( "In a similar way you should be able to see that 5 is a common factor in both 5x and 35. Now consider what does 5 need to be multiplied by to get 5x - 35. Hopefully you can work out that the two factors are 5 and (x-7).<BR>\n" );
document.write( "So the original problem can be rewritten as<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284x-28%29%2F%285x-35%29 ALIGN=MIDDLE  ALT=\"%284x-28%29%2F%285x-35%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284%28x-7%29%29%2F%285%28x-7%29%29 ALIGN=MIDDLE  ALT=\"%284%28x-7%29%29%2F%285%28x-7%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The common factor of (x-7) can now be cancelled out<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284cross%28%28x-7%29%29%29%2F%285cross%28%28x-7%29%29%29 ALIGN=MIDDLE  ALT=\"%284cross%28%28x-7%29%29%29%2F%285cross%28%28x-7%29%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F5 ALIGN=MIDDLE  ALT=\"4%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
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