document.write( "Question 755098: How to work this problem
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document.write( "-5(1-2z)+4(3-z)=7(3+2)
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document.write( "I have work this problem for a while and I still can't get it please help \n" );
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Algebra.Com's Answer #459505 by pragya.ban@gmail.com(32)![]() ![]() ![]() You can put this solution on YOUR website! -5(1-2z)+4(3-z)=7(3+2)\r \n" ); document.write( "\n" ); document.write( "The basic idea of this equation is to distribute everything first. \n" ); document.write( " (Remember the Order of Operations: [P]arenthesis [E]xponents [M]ultiplication [D]ivision [A]ddition [S]ubtraction)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1. If you distribute, it should look like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-5+10z+12-4z= 7(5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "*The negative sign from -2z changes to a positive sign because when two negative numbers multiply (-5 and -2z in this case), they result in a positive answer (+10z). However, when there is one negative number (-z) and one positive number (+4) multiplied, it equals to a negative answer (-4z).*\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. The next step is to group like terms together and operate in between them:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-5+12)+(10z-4z)=35\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7+6z=35\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3. Now solve like normal. Subtract 7 from both sides and then divide by 6.\r \n" ); document.write( "\n" ); document.write( "6z=35-7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z=28/6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z=4.66\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To check your answer replace z with 4.66 and see if it equals to 35. \n" ); document.write( " |