document.write( "Question 754846: The product of 3 consecutive numbers when divided by each of them in turn , the sum of three quotient will be 74 .what are the numbers ? \n" ); document.write( "
Algebra.Com's Answer #459422 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The product of 3 consecutive numbers when divided by each of them in \n" ); document.write( " turn, the sum of three quotient will be 74. \n" ); document.write( "what are the numbers? \n" ); document.write( ": \n" ); document.write( "The product \n" ); document.write( "x(x+1)(x+2) = x^3 + 3x^2 + 2x \n" ); document.write( ": \n" ); document.write( "The three quotients \n" ); document.write( "divisor: quotient \n" ); document.write( "x: (x+1)(x+2) \n" ); document.write( "(x+1): x(x+2) \n" ); document.write( "(x+2): x(x+1) \n" ); document.write( ": \n" ); document.write( "The sum \n" ); document.write( "[(x+1)(x+2)] + [x(x+2)] + [x(x+1)] = 74 \n" ); document.write( "(x^2 + 3x + 2) + (x^2 + 2x) + (x^2 + x) = 74 \n" ); document.write( "combine like terms \n" ); document.write( "3x^2 + 6x + 2 = 74 \n" ); document.write( "A quadratic equation \n" ); document.write( "3x^2 + 6x + 2 - 74 = 0 \n" ); document.write( "3x^2 + 6x - 72 = 0 \n" ); document.write( "Factors to: \n" ); document.write( "(3x + 18)(x - 4) = 0 \n" ); document.write( "Positive solution is what we want here \n" ); document.write( "x = 4 \n" ); document.write( "4, 5, 6 are the numbers\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |