document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65413>Question 65413</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618044302/algebrahomeworkh>algebra sctructure and method book 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Laurie left home and ran to the lake at 10 mi/h. She ran back home at 8 mi/h. If the entire trip took 27 minutes, how far did she run in all? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45940 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We'll use the formula distance (d) = rate(r) times time (t) or d=rt\r<BR>\n" );
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document.write( "Let d1=distance to the lake<BR>\n" );
document.write( "r1=her rate to the lake (10mi/hr)<BR>\n" );
document.write( "t1=her time to the lake\r<BR>\n" );
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document.write( "Let d2=distance from the lake<BR>\n" );
document.write( "r2=her rate from the lake (8 mi/hr)<BR>\n" );
document.write( "t2=her time from the lake\r<BR>\n" );
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document.write( "Now we know the following:\r<BR>\n" );
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document.write( "(a.)   t1+t2= 27 mim<BR>\n" );
document.write( "(b.)   d1=d2<BR>\n" );
document.write( "(c.)   Total distance is 2d1 or 2d2 or d1+d2<BR>\n" );
document.write( "(d.)   d1=r1t1=10t1<BR>\n" );
document.write( "(e.)   d2=r2t2=8t2\r<BR>\n" );
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document.write( "Since d1=d2, we know that:<BR>\n" );
document.write( "10t1=8t2<BR>\n" );
document.write( "t1=(8/10)t2<BR>\n" );
document.write( "t1=(4/5)t2 substitute for t1 in (a.) above and we have<BR>\n" );
document.write( "(4/5)t2+t2=27min multiply both sides by 5 to get rid of the fraction<BR>\n" );
document.write( "4t2+5t2=135min<BR>\n" );
document.write( "9t2=135<BR>\n" );
document.write( "t2=15min or (1/4) hr <BR>\n" );
document.write( "t1=27-15=12min or (1/5)hr\r<BR>\n" );
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document.write( "Now substitute the times in (d.) and/or (e.) to get half the total distance that he ran.\r<BR>\n" );
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document.write( "From (d.) <BR>\n" );
document.write( "d1=10(1/5)=2 miles<BR>\n" );
document.write( "From (e.)<BR>\n" );
document.write( "d2=8(1/4)=2 miles\r<BR>\n" );
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document.write( "Total distance =<BR>\n" );
document.write( "d1+d2=4 miles\r<BR>\n" );
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document.write( "Happy Holidays----ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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