document.write( "Question 754890: e^x=2e^(x/2)+35 \n" ); document.write( "

Algebra.Com's Answer #459380 by stanbon(75887) $\"\"$ $\"About$

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e^x=2e^(x/2)+35
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\n" ); document.write( "Quadratic in e^(x/2):
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\n" ); document.write( "(e^(x/2))^2 -2e^(x/2) - 35 = 0
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\n" ); document.write( "Factor:
\n" ); document.write( "(e^(x/2)-7)(e^(x/2)+5) = 0
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\n" ); document.write( "Positive solution:
\n" ); document.write( "e^(x/2) = 7
\n" ); document.write( "(x/2) = ln(7)
\n" ); document.write( "x = 2*ln(7)
\n" ); document.write( "x = ln(49)
\n" ); document.write( "==================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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