document.write( "Question 65414: How do you graph x-y=12 on the rectangular coordinate system where you have the x- and y-axes Do I first put this in a slope -intercept form; y=mx+b
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Algebra.Com's Answer #45938 by amran(4) $\"\"$ $\"About$

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There are a number of way you can do this. Just remember that you need at least two distinct points or a slope-point to draw a specific line.
\n" ); document.write( "Below we shall make use two intercept points formula $\"+x%2Fa+%2B+y%2Fb+=+1\"$ .
\n" ); document.write( "Divide the equation by 12
\n" ); document.write( " $\"x%2F12+-+y%2F12+=12%2F12\"$
\n" ); document.write( " $\"x%2F12%2B+y%2F-12+=1\"$ .
\n" ); document.write( "Hence the graph passes through the points (12,0) and (0,-12).
\n" ); document.write( "Mark the two points in the coordinate system and draw a line passing these points.\r
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\n" ); document.write( "\n" ); document.write( " $\"+graph%28200%2C200%2C-10%2C20%2C-20%2C10%2Cx-12%29\"$ \n" ); document.write( "

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