document.write( "Question 65404: 3a/a-2-5a/a+1 \n" ); document.write( "
Algebra.Com's Answer #45927 by stanbon(75887)\"\" \"About 
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3a/a-2-5a/a+1
\n" ); document.write( "LCD is (a-2)(a+1)
\n" ); document.write( "Write each fraction over the lcd as follows:
\n" ); document.write( "3a(a+1)/lcd - 5a(a-2)/lcd
\n" ); document.write( "Combine the numerators over a common denominator:
\n" ); document.write( "[3a^2+3a-5a^2+10a]/lcd
\n" ); document.write( "[-2a^2+13a]/[a_2)(a+1)]
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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