document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65402>Question 65402</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I worked this problem a million times and can get the right answer can anyone help?<BR>\n" );
document.write( "(g-8)+4=-12+3g </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45926 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45926\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given expression is: \r<BR>\n" );
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document.write( "(g-8) + 4 = -12 + 3g \r<BR>\n" );
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document.write( "To solve this equation for \"g\", we shall first remove the brackets, and then simplify them by grouping all the like terms.\r<BR>\n" );
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document.write( "g - 8 + 4 = -12 + 3g \r<BR>\n" );
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document.write( "g - 4 = -12 + 3g \r<BR>\n" );
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document.write( "Subtracting (12 - g) from both the sides: \r<BR>\n" );
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document.write( "12 - 4 = 3g - g \r<BR>\n" );
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document.write( "8 = 2g \r<BR>\n" );
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document.write( "Therefore,  g = 8/2 \r<BR>\n" );
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document.write( "g = 2\r<BR>\n" );
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document.write( "Hence, the solution.\r<BR>\n" );
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document.write( "Happy calculating!!!!!!... </SPAN>\n" );
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