document.write( "Question 754555: If geoff has 184 pounds of 94% lead and 6% antimony, how much tin would he need to add to have 90%lead 5% each tin and antimony? \n" ); document.write( "

Algebra.Com's Answer #459256 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Geoff has 184 pounds of 94% lead and 6% antimony,
\n" ); document.write( "How much tin would he need to add to have 90% lead 5% each tin and
\n" ); document.write( " antimony?
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\n" ); document.write( "Find amt of Lead and antimony in the mixture initially
\n" ); document.write( ".94(184) = 172.96 lb
\n" ); document.write( ".06(184) = 11.04 lb
\n" ); document.write( ":
\n" ); document.write( "Since the amt of tin is to be the same as the amt of antimony,
\n" ); document.write( "amt of tin = 11.04 lb added
\n" ); document.write( ":
\n" ); document.write( "Check this, find the total amt of the mixture
\n" ); document.write( "184 + 11.04 = 195.04 lb of mixture now
\n" ); document.write( ":
\n" ); document.write( "See if that checks out
\n" ); document.write( "172.96/195.04 * 100 = 89%
\n" ); document.write( "11.04/195.04 * 100 = 5.66% of tin and Antimony
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\n" ); document.write( "Total percent: 100.32 which is about as close as you will get it
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