document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=754662>Question 754662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how can i solve 2/6&#8730;8? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #459247 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=459247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You must use a method called rationalisation.<BR>\n" );
document.write( "You multiply your equation by sqroot8/sqroot8 <BR>\n" );
document.write( "which is really equal to 1/1 or 1\r<BR>\n" );
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document.write( "       2/ 6 sqroot8  x  sqroot8/sqroot8  \r<BR>\n" );
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document.write( "            = 2 sqroot 8/ 6 x 8   (sqroot8 x sqroot8 = 8)\r<BR>\n" );
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document.write( "                 sqroot 8 = 2 sqroot 2\r<BR>\n" );
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document.write( "            (So your 2sqroot 8 becomes 4 sqroot 2)\r<BR>\n" );
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document.write( "             Equation is:-  4 sqroot 2/ 48\r<BR>\n" );
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document.write( "             Cancel 4 and 48  and you are left with:-\r<BR>\n" );
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document.write( "                           sqroot 2/12\r<BR>\n" );
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document.write( " Hope this helps<BR>\n" );
document.write( ":-)  </SPAN>\n" );
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