document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65389>Question 65389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the first three terms of the arithmetic series in which asub1= 5  asubn= 33 and Ssubn= 152 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45921 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45921\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the first three terms of the arithmetic series in which asub1= 5  asubn= 33 and Ssubn= 152<BR>\n" );
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document.write( "a(1)=5<BR>\n" );
document.write( "a(n)=a(1)+(n-1)d=33<BR>\n" );
document.write( "5+(n-1)d=33<BR>\n" );
document.write( "(n-1)d=28<BR>\n" );
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document.write( "S(n)=(n/2)(a(1)+a(n))=152<BR>\n" );
document.write( "(n/2)(5+33)=152<BR>\n" );
document.write( "n*38=304<BR>\n" );
document.write( "n=8<BR>\n" );
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document.write( "Since n=8 and (n-1)d=28<BR>\n" );
document.write( "7d=28<BR>\n" );
document.write( "d=4<BR>\n" );
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document.write( "So, <BR>\n" );
document.write( "a(1)=5<BR>\n" );
document.write( "a(2)=5+d=5+4=9<BR>\n" );
document.write( "a(3)5+2d=5+8=13<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );