document.write( "Question 65385: Combine:( 2√7+√2)(3√7-42√2
\n" ); document.write( "5) Simplify by rationalizing the denominator:
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\n" ); document.write( "√6–√3
\n" ); document.write( "——————
\n" ); document.write( "√6+√3
\n" ); document.write( "thank you so much
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Algebra.Com's Answer #45920 by stanbon(75887)\"\" \"About 
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Combine:( 2√7+√2)(3√7-42√2)
\n" ); document.write( "F: 6*7=42
\n" ); document.write( "O:-84sqrt14
\n" ); document.write( "I: 3sqrt14
\n" ); document.write( "L:-42*2=-84
\n" ); document.write( "Combine to get: -42-81sqrt14
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\n" ); document.write( "\n" ); document.write( "5) Simplify by rationalizing the denominator: \r
\n" ); document.write( "\n" ); document.write( "√6–√3
\n" ); document.write( "——————
\n" ); document.write( "√6+√3
\n" ); document.write( "------------
\n" ); document.write( "(sqrt6 - sqrt3)/(sqrt6+sqrt3)
\n" ); document.write( "Multiply numerator and denominator by (sqrt6-sqrt3) to get:
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\n" ); document.write( "(sqrt6-sqrt3)(sqrt6-sqrt3)/(6-3)
\n" ); document.write( "=[6-2sqrt18+3)/3
\n" ); document.write( "=[9-6sqrt2]/3
\n" ); document.write( "=[3-2sqrt2]
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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