document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=754518>Question 754518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jane leave Oklahoma city traveling in her truck at a rate of 40 miles per hour. One hour later Harrison leaves Oklahoma city traveling in his car at a rate of 60 miles per hour. How long will it take Harrison to catch up with jane?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #459164 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=459164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jane leave Oklahoma city traveling in her truck at a rate of 40 miles per hour. One hour later Harrison leaves Oklahoma city traveling in his car at a rate of 60 miles per hour. How long will it take Harrison to catch up with jane?<BR>\n" );
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document.write( "let x=time it will take Harrison to catch up with jane? (travel time)<BR>\n" );
document.write( "x+1= Jane's travel time<BR>\n" );
document.write( "distance=speed*travel time (same for both jane and harrison)<BR>\n" );
document.write( "40(x+1)=60(x)<BR>\n" );
document.write( "40x+40=60x<BR>\n" );
document.write( "20x=40<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "time it will take Harrison to catch up with jane=2 hrs </SPAN>\n" );
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