document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65380>Question 65380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> joe has $4.70 in half-dollars, quarters, and dimes. The number of quarters is 10 less than twice the number of dimes. The number of half-dollars decreased by the number of quarters is 2. Find the umber of coins of each type. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45916 by </B><A HREF=/tutors/aboutme.mpl?userid=Zizzle><B>Zizzle(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Zizzle><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number of dimes = d<BR>\n" );
document.write( "Let the number of quarters = 2d-10<BR>\n" );
document.write( "Let the number of half dollars = 2d-8\r<BR>\n" );
document.write( "\n" );
document.write( ".10(d) + .25(2d-10) + .50(2d-8) = 4.70<BR>\n" );
document.write( ".10d + .5d-2.5 + 1d-4 = 4.70<BR>\n" );
document.write( "1.6d - 6.5 = 4.70<BR>\n" );
document.write( "1.6d = 4.70+6.5<BR>\n" );
document.write( "1.6d = 11.20<BR>\n" );
document.write( "d=7\r<BR>\n" );
document.write( "\n" );
document.write( "The number of dimes = 7<BR>\n" );
document.write( "The number of quarters = 2(7)-10, which is equal to 4<BR>\n" );
document.write( "The number of half dollars = 2(7)-8, which is equal to 6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );