document.write( "Question 754534: Two projectiles are simultaneously launched. The height in meters , h(base 1) t and h(base 2)t of the first and second projectiles as a function of time t in seconds since the launch are given by the rules h(base 1)t = -2t^2+ 20t + 50 and h(base 2) = 2t +66 .
\n" ); document.write( "a) How long after their launch will the two projectiles be at the same height?
\n" ); document.write( "b) Over what interval of time since the launch is the first projectile higher than the second?\r
\n" ); document.write( "\n" ); document.write( "Can you please help me out? Thanks so much in advance:)
\n" ); document.write( "Can you also please show the steps it would really help me understand:)
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Algebra.Com's Answer #459148 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
h(base 1)t = -2t^2+ 20t + 50 and h(base 2) = 2t +66 .
\n" ); document.write( "a) How long after their launch will the two projectiles be at the same height?
\n" ); document.write( "Solve:
\n" ); document.write( "-2t^2 + 20t + 50 = 2t+66
\n" ); document.write( "-2t^2 + 18t - 16 = 0
\n" ); document.write( "t^2 - 9t + 8 = 0
\n" ); document.write( "(t-8)(t-1) = 0
\n" ); document.write( "t = 1 second (1st time they are at the same height)
\n" ); document.write( "t = 8 seconds (2nd time they are at the same height)
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\n" ); document.write( "b) Over what interval of time since the launch is the first projectile higher than the second?
\n" ); document.write( "1sec < t < 8 sec
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\n" ); document.write( "\"graph%28400%2C400%2C-10%2C10%2C-10%2C100%2C-2x%5E2%2B20x%2B50%2C2x%2B66%29\"
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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