document.write( "Question 754534: Two projectiles are simultaneously launched. The height in meters , h(base 1) t and h(base 2)t of the first and second projectiles as a function of time t in seconds since the launch are given by the rules h(base 1)t = -2t^2+ 20t + 50 and h(base 2) = 2t +66 .
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document.write( "a) How long after their launch will the two projectiles be at the same height?
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document.write( "b) Over what interval of time since the launch is the first projectile higher than the second?\r
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document.write( "Can you please help me out? Thanks so much in advance:)
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document.write( "Can you also please show the steps it would really help me understand:) \n" );
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Algebra.Com's Answer #459148 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! h(base 1)t = -2t^2+ 20t + 50 and h(base 2) = 2t +66 . \n" ); document.write( "a) How long after their launch will the two projectiles be at the same height? \n" ); document.write( "Solve: \n" ); document.write( "-2t^2 + 20t + 50 = 2t+66 \n" ); document.write( "-2t^2 + 18t - 16 = 0 \n" ); document.write( "t^2 - 9t + 8 = 0 \n" ); document.write( "(t-8)(t-1) = 0 \n" ); document.write( "t = 1 second (1st time they are at the same height) \n" ); document.write( "t = 8 seconds (2nd time they are at the same height) \n" ); document.write( "-------------------------------------------------------------- \n" ); document.write( "b) Over what interval of time since the launch is the first projectile higher than the second? \n" ); document.write( "1sec < t < 8 sec \n" ); document.write( "========================== \n" ); document.write( " \n" ); document.write( "=============================== \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " \n" ); document.write( " |