document.write( "Question 65379This question is from textbook
\n" ); document.write( ": a trip between two towns in montana takes 4 hours under ideal conditions. The first 150 miles of the trip is on a interstate, and the second 130 miles is on a highway with a speed limit that is 10 miles per hour less than on interstate\r
\n" ); document.write( "\n" ); document.write( "a)if x represents the speed limit on the interstate, write an expression that represents the time spend at that speed
\n" ); document.write( "b) write an expression for the time spent on the other highway
\n" ); document.write( "c)write and solve an equation to find the speed limit on the interstate and on the highway
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Algebra.Com's Answer #45914 by checkley71(8403)\"\" \"About 
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150/X+130/(X-10)=4
\n" ); document.write( "[150(X-10)+130X]/X(X-10)=4
\n" ); document.write( "(150X-1500+130X]/(X^2-10X)=4
\n" ); document.write( "280X-1500=4X^2-40X=0
\n" ); document.write( "4X^2-40X-280X+1500=0
\n" ); document.write( "4X^2-320X+1500=0 USING THE QUADRATIC EQUATION X=(-B+-SQRTB^2-4AC])/2A WE GET
\n" ); document.write( "X=(320+-SQRT[-320*-320]-[4*4+1500])/2*4
\n" ); document.write( "X=(320+-SQRT[102400-24000])/8
\n" ); document.write( "X=(320+-SQRT[78400])/8
\n" ); document.write( "X=(320+-280)/8
\n" ); document.write( "X=(320+280)/8
\n" ); document.write( "X=600/8
\n" ); document.write( "X=75 MPH SOLUTION FOR THE INTERSTATE SPEED. 75-10=65 MPH FOR THE HIGHWAY.
\n" ); document.write( "PROOF
\n" ); document.write( "150/75+130/65=4
\n" ); document.write( "2+2=4
\n" ); document.write( "4=4
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\n" ); document.write( "MERRY CHRISTMAS
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