document.write( "Question 65331: a rectangle is three times as long as it is wide. If its lenght and width are both decreased by 2 cm, its area is decreased by 36cm(2). Find its original dimensions. Make a sketch. \n" ); document.write( "

Algebra.Com's Answer #45910 by josmiceli(19441) $\"\"$ $\"About$

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$\"3x%2Ax+=+A\"$
\n" ); document.write( " $\"3x%5E2+=+A\"$
\n" ); document.write( " $\"%283x+-+2%29%28x+-+2%29+=+A+-+36\"$
\n" ); document.write( " $\"3x%5E2+-+8x+%2B+4+=+A+-+36\"$
\n" ); document.write( "substitute A for $\"3x%5E2\"$
\n" ); document.write( " $\"A+-+8x+%2B+4+=+A+-+36\"$
\n" ); document.write( "subtract A from both sides
\n" ); document.write( " $\"-8x+%2B+4+=+-36\"$
\n" ); document.write( " $\"8x+=+36+%2B+4\"$
\n" ); document.write( " $\"8x+=+40\"$
\n" ); document.write( " $\"x+=+5\"$
\n" ); document.write( " $\"A+=+3%2A5%5E2\"$
\n" ); document.write( " $\"A+=+75\"$ cm2 answer
\n" ); document.write( "check
\n" ); document.write( " $\"%283x+-+2%29%28x+-+2%29+=+A+-+36\"$
\n" ); document.write( " $\"%283%2A5+-+2%29%285+-+2%29+=+A+-+36\"$
\n" ); document.write( " $\"13%2A3+=+A+-+36\"$
\n" ); document.write( " $\"A+=+39+%2B+36\"$
\n" ); document.write( " $\"A+=+75\"$
\n" ); document.write( "OK \n" ); document.write( "

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