document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=754383>Question 754383</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am stuck on this: 2 complementary angles, all part of the same problem. 1st one is 2x+3 and y the next is x+12 and y solve for x and y I get how to calculate for x just confused how to get y?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #459037 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=459037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am stuck on this: 2 complementary angles, all part of the same problem. 1st one is 2x+3 and y the next is x+12 and y solve for x and y I get how to calculate for x just confused how to get y? <BR>\n" );
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document.write( "Not clear what \"and y\" means.<BR>\n" );
document.write( "(2x+3) + (x+12) = 180 degs<BR>\n" );
document.write( "3x+15 = 180<BR>\n" );
document.write( "x = 55<BR>\n" );
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