document.write( "Question 754316: How much 40% acid solution should be mixed with 2 gallons of 60% acid solution in order to het a 50% acid solution? \n" ); document.write( "

Algebra.Com's Answer #459008 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = gallons of 40% solution needed
\n" ); document.write( " $\"+.4x+\"$ = gallons of acid in 40% solution
\n" ); document.write( " $\"+.6%2A2+=+1.2+\"$ gallons of acid in 60% solution
\n" ); document.write( "-----------------
\n" ); document.write( " $\"+%28+.4x+%2B+1.2+%29+%2F+%28+2+%2B+x+%29+=+.5+\"$
\n" ); document.write( " $\"+.4x+%2B+1.2+=+.5%2A%28+2+%2B+x+%29+\"$
\n" ); document.write( " $\"+.4x+%2B+1.2+=+1+%2B+.5x+\"$
\n" ); document.write( " $\"+.1x+=+.2+\"$
\n" ); document.write( " $\"+x+=+2+\"$
\n" ); document.write( "2 gallons of 40% solution are needed
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.4x+%2B+1.2+%29+%2F+%28+2+%2B+x+%29+=+.5+\"$
\n" ); document.write( " $\"+%28+.4%2A2+%2B+1.2+%29+%2F+%28+2+%2B+2+%29+=+.5+\"$
\n" ); document.write( " $\"+2+%2F+4+=+.5+\"$
\n" ); document.write( " $\"+2+=+2+\"$
\n" ); document.write( "OK \n" ); document.write( "

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