document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=754317>Question 754317</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sum of three numbers is twenty five the second number is twice the first the third number exceed the second by five find the numbers<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #458988 by </B><A HREF=/tutors/aboutme.mpl?userid=anteater><B>anteater(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=anteater><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=458988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call your first number x.\r<BR>\n" );
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document.write( "Your second number is twice the first, so it is 2x.\r<BR>\n" );
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document.write( "Your third number exceeds the second number by 5, so it is 2x + 5.\r<BR>\n" );
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document.write( "When you add these three numbers up, the sum is 25:\r<BR>\n" );
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document.write( "x +  2x  +  (2x + 5)  =  25\r<BR>\n" );
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document.write( "Combine \"like\" terms:\r<BR>\n" );
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document.write( "5x + 5 = 25\r<BR>\n" );
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document.write( "Now, isolate (or solve for) x. First, subtract 5 from both sides of the equation:\r<BR>\n" );
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document.write( "5x + 5 - 5 = 25 - 5\r<BR>\n" );
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document.write( "5x = 20\r<BR>\n" );
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document.write( "Then, divide both sides of the equation by 5:\r<BR>\n" );
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document.write( "5x/5  = 20/5\r<BR>\n" );
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document.write( "x = 4\r<BR>\n" );
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document.write( "So our first number is 4.\r<BR>\n" );
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document.write( "The second number is twice this, or 8.\r<BR>\n" );
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document.write( "The third number exceeds 8 by 5. Since 8 + 5 = 13, 13 is our third number.\r<BR>\n" );
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document.write( "Finally, \r<BR>\n" );
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document.write( "4  +  8  +  13  =  25\r<BR>\n" );
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document.write( "I hope this was helpful! :)\r<BR>\n" );
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