document.write( "Question 754329: 25+15y+2y^2=228 \n" ); document.write( "
Algebra.Com's Answer #458981 by vidya pattar(14)![]() ![]() ![]() You can put this solution on YOUR website! Solution:\r \n" ); document.write( "\n" ); document.write( "Here you have : \n" ); document.write( "25 + 15y + 2y^2 = 228 \n" ); document.write( "now try to get rid of 228 from the right side. \n" ); document.write( "25 - 228 +15y + 2y^2 =0 \n" ); document.write( "now combine the like terms : \n" ); document.write( "-223 + 15y + 2y^2 = 0 \n" ); document.write( "now arange them in increasing order. \n" ); document.write( "2y^2 +15y - 223 = 0 \n" ); document.write( "now to solve for x you have use the quadratic rquation:
\n" ); document.write( "\n" ); document.write( "so here you get \" \r \n" ); document.write( "\n" ); document.write( "x = (-15 +/- sqrt ( 15^2 - 4(2)(-223)) )/ 2(2) \n" ); document.write( "x = -15 +/- sqrt ( 2009)/4\r \n" ); document.write( "\n" ); document.write( "hence we get after calculation x = 7.45 and x = - 14.955 \r \n" ); document.write( "\n" ); document.write( "Thanks & regards\r \n" ); document.write( "\n" ); document.write( "Vidya pattar \n" ); document.write( " |