document.write( "Question 754302: A screening program tests people for hookworm infection, and treats them if they are found to be infected. A diagnosis of hookworm infection is made when a hookworm egg is identified by microscopy in a stool specimen, usually involving multiple slides(sample from the stool specimen). The sensitivity of the stool exam is 75% per slide i.e. if a person is infected, there is a 75% chance that the microscopist will identify an egg on a single slide from the stool specimen. How many slides will need to be taken from a given stool specimen to ensure that an infected person will have a probability of at least 99% of receiving treatment? \n" ); document.write( "
Algebra.Com's Answer #458957 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A screening program tests people for hookworm infection, and treats them if they are found to be infected. A diagnosis of hookworm infection is made when a hookworm egg is identified by microscopy in a stool specimen, usually involving multiple slides(sample from the stool specimen). The sensitivity of the stool exam is 75% per slide i.e. if a person is infected, there is a 75% chance that the microscopist will identify an egg on a single slide from the stool specimen. How many slides will need to be taken from a given stool specimen to ensure that an infected person will have a probability of at least 99% of receiving treatment? \n" ); document.write( "--------------------- \n" ); document.write( "n = [z/E]^2*pq \n" ); document.write( "----------------- \n" ); document.write( "n = [2.5758/0.01]^2*0.75*0.25 = 12441 \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |