document.write( "Question 754279:
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document.write( "solve the radical equation. if there is no real solution, chose no solution \r\n" );
document.write( "3x = √20 - 3x

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Algebra.Com's Answer #458937 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "              3x = √20 - 3x\r\n" );
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document.write( "Square both sides of the equation:\r\n" );
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document.write( "           (3x)² = (√20 - 3x)²\r\n" );
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document.write( "            3²x² = 20 - 3x\r\n" );
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document.write( "             9x² = 20 - 3x\r\n" );
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document.write( "   9x² + 3x - 20 = 0\r\n" );
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document.write( "(3x - 4)(3x + 5) = 0\r\n" );
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document.write( "Use the zero-factor principle:\r\n" );
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document.write( "3x - 4 = 0;  3x + 5 = 0\r\n" );
document.write( "    3x = 4;      3x = -5\r\n" );
document.write( "     x = \"4%2F3\";      x = \"%28-5%29%2F3\"      \r\n" );
document.write( "                  x = \"-5%2F3\"\r\n" );
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document.write( "We must check radical equations to see if answers \r\n" );
document.write( "are solutions or extraneous answers:\r\n" );
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document.write( "Checking x = \"4%2F3\" in original equation:\r\n" );
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document.write( "\"3%284%2F3%29=sqrt%2820-3%284%2F3%29%29\"\r\n" );
document.write( "\"cross%283%29%284%2Fcross%283%29%29=sqrt%2820-cross%283%29%284%2Fcross%283%29%29%29\"\r\n" );
document.write( "\"4=sqrt%2820-4%29\"\r\n" );
document.write( "\"4=sqrt%2816%29\"\r\n" );
document.write( "\"4=4\"\r\n" );
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document.write( "So \"4%2F3\" is a solution.\r\n" );
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document.write( "Checking x = \"-5%2F3\" in original equation:\r\n" );
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document.write( "\"3%28-5%2F3%29=sqrt%2820-3%28-5%2F3%29%29\"\r\n" );
document.write( "\"cross%283%29%28-5%2Fcross%283%29%29=sqrt%2820-cross%283%29%28-5%2Fcross%283%29%29%29\"\r\n" );
document.write( "\"-5=sqrt%2820-%28-5%29%29\"\r\n" );
document.write( "\"-5=sqrt%2820%2B5%29%29\"\r\n" );
document.write( "\"-5=sqrt%2825%29\"\r\n" );
document.write( "\"-5=5\"\r\n" );
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document.write( "So \"-5%2F3\" is not a solution, but an extraneous answer.\r\n" );
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document.write( "Therefore the only solution is \"4%2F3\".\r\n" );
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document.write( "Edwin
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