document.write( "Question 65329: A plane flies 720 miles against a steady 30 mi/hr headwind and then returns to the same point with the wind. If the entire trip takes 10 hours, what is the plane’s speed in still air? \n" ); document.write( "
Algebra.Com's Answer #45883 by stanbon(75887)\"\" \"About 
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\n" ); document.write( "A plane flies 720 miles against a steady 30 mi/hr headwind and then returns to the same point with the wind. If the entire trip takes 10 hours, what is the plane’s speed in still air?
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\n" ); document.write( "Let p be plane speed
\n" ); document.write( "Against the wind DATA:
\n" ); document.write( "distance= 720 miles ; Rate= p-30 mph ; time = d/r= 720/(p-30) hrs.
\n" ); document.write( "-----------------
\n" ); document.write( "With the wind DATA:
\n" ); document.write( "distance =720 miles ; rate = p+30 mph ; time = d/r = 720/(p+30) hrs.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "time with + time against = 10 hrs
\n" ); document.write( "720/(p+30) + 720/(p-30)= 10
\n" ); document.write( "Divide thru by 720 to get:
\n" ); document.write( "1/(p+30) + 1/(p-30)= 1/72
\n" ); document.write( "Multiply thru by (p+30)(p-30) to get:
\n" ); document.write( "p-30+p+30=(1/72)(p^2-900)
\n" ); document.write( "Simplify the left side to get:
\n" ); document.write( "2p=(1/72)(p^2-900)
\n" ); document.write( "Multiply both sides by 72 to get:
\n" ); document.write( "144p=p^2-900
\n" ); document.write( "Rearrange:
\n" ); document.write( "p^2-144p-900=0
\n" ); document.write( "Use the quadratic formula to get:
\n" ); document.write( "p=[144+-sqrt(144^2-4*-900)]/2
\n" ); document.write( "p=[144+-156]/2
\n" ); document.write( "Select the positive solution to get:
\n" ); document.write( "p=[144+156]/2=300/2=150 mph
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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